Test Series - computer fundamental

Test Number 62/95

Q: Separation of user logical memory and physical memory is ___________
A. Memory control
B. Memory management
C. Memory sharing
D. Virtual memory
Solution: The separation of user logical memory and physical memory is called virtual memory. Only part of the program needs to be in memory for execution.
Q: Logical Address space can be larger than physical address space.
A. True
B. False
C. none
D. ..
Solution: The statement is true. Since, a part of the program needs to be in memory for the process of execution, the logical space can therefore be much larger than the physical address space.
Q: Virtual Memory can be implemented via __________
A. Demand Paging
B. Logical paging
C. Structural way
D. Simple division
Solution: Demand paging can implement virtual memory. Another way is demand segmentation.
Q: COW stands for?
A. Copy over write
B. Convert over write
C. Count over write
D. Copy over write
Solution: COW stands for Copy over write. COW allows both parent and child processes to share the same pages initially.
Q: LRU stands for?
A. Least Recently used
B. Less Recently used
C. Least Recurrently used
D. Least Randomly used
Solution: LRU stands for Least Recently used. LRU is least recently used. It replaces page with the smallest count.
Q: An allocation that uses a proportional allocation scheme using priorities rather than size.
A. Priority allocation
B. File allocation
C. Preference allocation
D. Simple allocation
Solution: Priority allocation uses a proportional allocation scheme using priorities rather than size.
Q: A process selects a replacement frame from the set of all frames.
A. Local replacement
B. Global replacement
C. Block replacement
D. Module replacement
Solution: Global replacement process selects a replacement frame from the set of all frames; one process can take a frame from another.
Q: Any program, no matter how small, occupies an entire partition. This is called _____________
A. fragmentation
B. prior fragmentation
C. internal fragmentation
D. external fragmentation
Solution: It is called as internal fragmentation. Main memory use is inefficient. Any program, no matter how small, occupies an entire partition. This is called internal fragmentation.
Q: A process is busy swapping pages in and out.
A. Thrashing
B. Compaction
C. External Fragmentation
D. Division
Solution: Thrashing is the term used whenever a process is busy swapping pages in and put.
Q: ___________ is one or more physically contiguous pages.
A. Slab
B. Cache
C. Object
D. Allocator
Solution: Slab is one or more physically contiguous pages. Cache consists of one or more slabs.

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